- Calculate the LC-Sequence, as
`LCS`

; - return
`str1.length() + str2.length() - LCS.length()`

;

Example:

```
s1: "dynamic"
s2: "programming"
LC-sequence: "ami", length: 3
SCS (return) : 15
```

Explanation:

`S1`

and `s2`

has the longest common sequence `ami`

, with length `3`

. what we need to do is to add the remaining character to LCS.

We need to add `s1.length() - LCS.length()`

plus `s2.length() - LCS.length()`

number of characters to the LCS. Added up, the SCS would be `str1.length() + str2.length() - LCS.length()`

;