my_func = lambda num: “High” if num > 50
print(my_func(60))
my_func = lambda num: “High” if num > 50
print(my_func(60))
Hi Harsha!
The compiler is throwing error because you haven’t added the check for else
statement.
The correct code is given below:
my_func = lambda num: "high" if num > 50 else num
Hope it helps. If you still have any queries, please let us know.
Thank you!