how did the inner loop runs n(n-1)/2 times, can anyone please explain me
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Hello @Sumit_Dwivedi
Let us understand this question with the help of an example. Let’s assume n = 5. This means i will run 4 times i.e. for 0, 1, 2, 3, and 4. Now when i = 0, inner loop will not execute at all. For i = 1, inner loop will execute 1 time. For i = 2, inner loop will execute for 2 times. For i = 3, inner loop will execute for 3 times. So we can see a pattern over here. So for i = n, inner loop will execute for 0 + 1 + 2 + 3 + … + (n - 1) times. The sum of this series equals to n(n - 1)/2.
Hope this helps!