I am unable to understand how the output came for question 5? Can you please explain the concept?
Hi @Saurav_Kumar1 !!
In the given code:
package main
import "fmt"
func trace(s string) string {
fmt.Println("entering:", s)
return s
}
func un(s string) {
fmt.Println("leaving:", s)
}
func a() {
defer un(trace("a"))
fmt.Println("in a")
}
func b() {
defer un(trace("b"))
fmt.Println("in b")
a()
}
func main() {
b()
}
We have a series of functions a
, b
, trace
, and un
, and we use defer
statements to defer the execution of certain functions until the surrounding function returns.
Here’s the execution flow and the corresponding output of the program:
-
We start from the
main
function and callb()
. -
Inside
b()
, we defer theun(trace("b"))
statement. Sincetrace("b")
is called first, it will print “entering: b” and return “b”. -
Then, we print “in b”.
-
Next,
b()
callsa()
. -
Inside
a()
, we defer theun(trace("a"))
statement. Similarly,trace("a")
is called first, which prints “entering: a” and returns “a”. -
Then, we print “in a”.
-
Now, we start unwinding the deferred calls. The deferred function
un(trace("a"))
insidea()
is executed first, and it prints “leaving: a”. Thetrace("a")
function was deferred and executed at the end of thea()
function. -
Now, we are back in the
b()
function, and the deferred functionun(trace("b"))
is executed, printing “leaving: b”. Thetrace("b")
function was deferred and executed at the end of theb()
function.
So, the final output of the program will be:
entering: b
in b
entering: a
in a
leaving: a
leaving: b
The concept to understand here is that when a function is deferred using defer
, its execution is postponed until the surrounding function returns. The deferred functions are executed in a Last In, First Out (LIFO) order, meaning the most recently deferred function will be executed first, and so on until the first deferred function is executed.
I hope it helps. Happy Learning