how the output is 8
(y-- - (x = 4) is equal to 2
x += 2 is equal to 3
Course: https://www.educative.io/courses/basics-java-programming
Lesson: https://www.educative.io/courses/basics-java-programming/gkozn81Ly63
how the output is 8
(y-- - (x = 4) is equal to 2
x += 2 is equal to 3
Course: https://www.educative.io/courses/basics-java-programming
Lesson: https://www.educative.io/courses/basics-java-programming/gkozn81Ly63
Hi @Amir_Mohammed !!
Sure, letâ€™s go through the complete code step by step:
class Preincrement {
public static void main(String[] args) {
int x = 5;
int y = 5;
// The ++ operator changes the value
// of the variable, but you can also
// use the result in an expression:
System.out.println(x++); // post-increment
System.out.println(++y); // pre-increment
// assignment statements are also expressions.
// However, the code below is bad: it's too likely
// to be a typo; probably you wanted ==, the
// the equality comparison.
System.out.println(x = y);
// Truly horrible programming style:
System.out.println(x += (y-- - (x = 4) ));
}
}
int x = 5;
: Declares and initializes an integer variable x
with the value 5.
int y = 5;
: Declares and initializes another integer variable y
with the value 5.
System.out.println(x++);
: This line prints the current value of x
, which is 5, and then increments x
by 1 using the post-increment operator x++
. The post-increment operator evaluates to the current value of x
before the increment. So, after this line, x
becomes 6.
System.out.println(++y);
: This line increments y
by 1 using the pre-increment operator ++y
and then prints the updated value of y
, which is 6.
System.out.println(x = y);
: This line assigns the value of y
(which is 6) to x
, and then it prints the value of x
. So, this line will print 6.
System.out.println(x += (y-- - (x = 4)));
: This is the most complex line in the code.
y--
: The post-decrement operator y--
returns the current value of y
, which is 6, and then decrements y
by 1. So, y
becomes 5, and the expression evaluates to 6.
(x = 4)
: This assigns the value 4 to x
, and the expression evaluates to 4.
(y-- - (x = 4))
: We already determined that this whole expression evaluates to 6 - 4, which is 2.
x += (y-- - (x = 4))
: x
is currently 6. The compound assignment +=
adds the value of the right-hand side (2) to the current value of x
, making x
become 8.
The line finally prints the value of x
, which is 8.
So, the output of the complete code will be:
5
6
6
8
I hope this helps. Happy Learning